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September 16, 2014

September 16, 2014

Posted by **Caitlin** on Monday, March 1, 2010 at 2:26pm.

4sin^2x = 3cos^2x

- Maths -
**Reiny**, Monday, March 1, 2010 at 5:26pm4sin^2x = 3(1-sin^2x)

4sin^2x = 3 - 3sin^2x

7sin^2x = 3

sin^2x = 3/7

sinx = ±√(3/7), so x is in any of the 4 quadrants

In first quadrant I get x = 40.9 degrees

in II, x = 180 - 40.9

in III, x = 180+40.9

in IV, x = 360-40.9

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