A 0.53-kg billiard ball initially at rest is given a speed of 12 m/s during a time interval of 4.0 ms. What average force acted on the ball during this time?

1590 N

Use the rule that Impulse (which is force x time) equals momentum change.

F * t = M * V

Solve for F

To find the average force acting on the billiard ball, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a):

F = m * a

In this case, the mass of the billiard ball is given as 0.53 kg. To calculate the acceleration, we can use the kinematic equation:

a = (v_f - v_i) / t

Where:
v_f = final velocity
v_i = initial velocity
t = time interval

Since the billiard ball is initially at rest, the initial velocity (v_i) is 0 m/s. The final velocity (v_f) is given as 12 m/s. The time interval (t) is 4.0 ms, but we need to convert it to seconds:

t = 4.0 ms / 1000 = 0.004 s

Now we can calculate the acceleration:

a = (12 m/s - 0 m/s) / 0.004 s
a = 3000 m/s^2

Finally, we can calculate the average force:

F = 0.53 kg * 3000 m/s^2
F = 1590 N

Therefore, the average force acting on the billiard ball during this time interval is 1590 Newtons.

wrong

1325N