Wednesday
September 2, 2015

Homework Help: chemistry

Posted by aymal on Monday, March 1, 2010 at 1:32pm.

a student synthesized 6.895g of barium iodate monohydrate, Ba(IO3)2.H2O, by adding 30.00 mL of 5.912*10^-1M barium nitrate, Ba(NO3), to 50.00 mL of 9,004*10^-1 M sodium iodate, NaIO3
(1) write the chemical equation for the reaction of solutions of barium nitrate and sodium iodate
(2) calculate the percent yield of barium iodate monohydrate the student obtained in this experiment

When reviewing the procedure and calculations, the student found that a 4.912*10^-1 M barium nitrate solution had been used instead of a 5.912*10^-1 M solution
(3) calculate the percent yield of barium iodate monohydrate using 30.00 mL of 4.912*10^-1 M barium nitrate solution and 50.00 mL of 9.004*10^-1 M sodium iodate solution.
(4) calculate the percent error in the percent yield calculated in (2), compare with the correct percent yield calculated in (3)

Pleaaaaase, i do really neeeed help

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Members