I'm trying to write an equation for the reaction of zinc nitrate with aqueous ammonia. I know that zinc hyroxide is produced first but I don't really know how to write an equation for this. This is what I came up with:

Zn(NO3)2 + 2OH- --> Zn(OH)2 + 2NO3-

I'm not really sure whether to include the ammonia in the equation or what will happen to the NO3-. Should I put water instead of OH-?

Zn(NO3)2+NH4OH (aq) >>Zn(OH)2(s) + NH3NO3 (aq)

you can balance it.

To write the equation for the reaction of zinc nitrate (Zn(NO3)2) with aqueous ammonia (NH3), it's important to understand the chemistry behind the reaction. When zinc nitrate reacts with aqueous ammonia, zinc hydroxide (Zn(OH)2) and ammonium nitrate (NH4NO3) are formed.

Here's how to write the balanced equation:

1. Start by breaking down the reactants:
Zn(NO3)2 → Zn2+ + 2NO3-
NH3 → NH4+ + OH-

2. Next, identify which ions will react. In this case, the positively charged zinc ion (Zn2+) will react with the hydroxide ion (OH-).

3. Now, write the balanced equation by combining the reactants and products:
Zn2+ + 2OH- → Zn(OH)2

Note that the nitrate ions (NO3-) are spectator ions, meaning they do not participate in the reaction. Therefore, they are not included in the balanced equation.

The ammonia (NH3) is used as a reactant and is not included in the final equation because it does not participate in the formation of the products.

So, the final balanced equation for the reaction of zinc nitrate with aqueous ammonia is:
Zn(NO3)2 + 2NH3 + 2OH- → Zn(OH)2 + 2NH4NO3

Keep in mind that this is a simplified equation, and in reality, the reaction may occur in multiple steps. However, this balanced equation represents the overall reaction.