1) At what speed must a 75 kg basketball player leave the ground if he is to jump a vertical distance of 1.2 m? (ans: 4.8 m/s)
the potential energy change in gravity must equal the initial kinetic energy.
mgh=1/2 m v^2
v= sqrt (2gh)
mgh=1/2 m v^2
v= sqrt (2gh)