98N-T=10a
T-18.89N=3a
I worked on the problem and I end up getting two equations but now I have to find T and a.
For some reason, I cant solve it.
Thanks
98N-T=10a
T-18.89N=3a
I worked on the problem and I end up getting two equations but now I have to find T and a.
For some reason, I cant solve it.
Thanks
Nevermind i figure it out
great.
To find the values of T and a from the given equations, you need to solve the two equations simultaneously. Here's a step-by-step solution to help you:
1. Start with the given equations:
98N - T = 10a -- (Equation 1)
T - 18.89N = 3a -- (Equation 2)
2. To solve for T and a, we'll use a method called elimination. Multiply Equation 2 by 98 to eliminate the T term:
98T - 1879N = 294a -- (Equation 3)
3. Now, we can add Equation 1 and Equation 3 to eliminate the a term:
(98N - T) + (98T - 1879N) = 10a + 294a
Simplifying, we have:
98N - T + 98T - 1879N = 304a
Rearranging terms, we get:
97N + 97T = 304a -- (Equation 4)
4. Now, we can express T in terms of N from Equation 4:
T = 304a - 97N -- (Equation 5)
5. Substitute this expression for T back into Equation 1:
98N - (304a - 97N) = 10a
Simplifying, we get:
98N - 304a + 97N = 10a
Rearranging terms, we have:
195N - 304a = 10a
Combine like terms:
195N = 314a
Divide both sides by 314:
N = (314a) / 195 -- (Equation 6)
6. Now, you have an expression for N in terms of a. Plug this value back into Equation 5 to find T in terms of a:
T = 304a - 97 * ((314a) / 195)
Simplifying further, we get:
T = 304a - (97 * 314a) / 195
7. Finally, you have expressions for T and N in terms of a. Substitute any value of a to find the corresponding values of T and N.
Please note that these equations may not simplify further, and the values of T and N will depend on the value of a.