posted by Kate on .
h t t p : / / i m g 2 0 5 . i m a g e s h a c k . u s / i / c a p t u r e b b . j p g /
i am stuck on part c
how do i find work with out using the spring constant
work equals force parallel times displacement at which the force is acted during...
Work done by spring = .5 kx^2
Work = delta K
but delta K = 0 because the table top is frictionless
Work = delta U
delta U = 0 in this situation correct?
so I'm stuck...
i think it might be zero but .5 kx^2 would not give zero now would it...