October 5, 2015

Homework Help: Physics

Posted by Kate on Sunday, February 28, 2010 at 8:35pm.

h t t p : / / i m g 2 0 5 . i m a g e s h a c k . u s / i / c a p t u r e b b . j p g /

i am stuck on part c

how do i find work with out using the spring constant

work equals force parallel times displacement at which the force is acted during...

Work done by spring = .5 kx^2
Work = delta K

but delta K = 0 because the table top is frictionless

Work = delta U
delta U = 0 in this situation correct?

so I'm stuck...

i think it might be zero but .5 kx^2 would not give zero now would it...

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