Posted by Ana on Sunday, February 28, 2010 at 8:31pm.
solve the equation:
log(base2)^(x-3)log(base2)^5 = 2log(base2)^10
I don't know how to solve it, can someone help me? Please and thank you.
Algebra 2 - Reiny, Sunday, February 28, 2010 at 10:50pm
your notation makes no sense
on the right side you have
there is no such notation.
The expression on the left is even worse.
Algebra 2 - Ana, Sunday, February 28, 2010 at 10:57pm
this is exactly what my homework sheet says. this is not teacher made, it's from the book. 2log(base2)^10 = log(base2)^10^2 = log(base2)^100
Algebra 2 - Reiny, Sunday, February 28, 2010 at 11:17pm
In this and most forums the ^ is used as an exponent indicator
e.g. 2^3 = 23
looking at your last line in the previous reply, I will assume that by
2log(base2)^10 = log(base2)^10^2 = log(base2)^100 you really meant :
2log(base2)10 = log(base2)10^2 = log(base2)100
so your question of
log(base2)^(x-3)log(base2)^5 = 2log(base2)^10 is really
log(base2)(x-3)log(base2)5 = 2log(base2)10 or
log2(x-3)log25 = 2log2100
divide by log25
log2(x-3) = log2100/log25
log2(x-3) = log100/log5 = 2.861353
so x-3 = 2^2.861353
x-3 = 7.26697
x = 10.26697
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