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July 29, 2014

July 29, 2014

Posted by **Hannah** on Sunday, February 28, 2010 at 7:55pm.

tan x - sec^2 x / tan x

I do not know where to start.

- Pre-Cal -
**Reiny**, Sunday, February 28, 2010 at 8:07pmThe way you typed it ....

tan x - sec^2 x / tan x

= tanx - (1/cos^2x)(c0sx/sinx+

= tanx - 1/(sinxcosx)

= tanx - cscxsecx

- Pre-Cal -
**MathMate**, Sunday, February 28, 2010 at 11:42pmHannah,

if you continue by substituting sin and cos for the tan,csc and sec functions, you can simplify further. This will be left as an exercise for yourself.

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