How many moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm and 25 degrees celcius
How many moles of oxygen will occupy a volume of 2.5 L at 1.2 atm and 25C
To calculate the number of moles of oxygen, we can use the Ideal Gas Law equation:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
First, let's convert the given values to the appropriate units:
- Pressure (P): 1.2 atm
- Volume (V): 2.5 liters
- Temperature (T): 25 degrees Celsius
Convert Celsius to Kelvin by adding 273.15:
T = 25 + 273.15 = 298.15 K
Now, we can rearrange the Ideal Gas Law equation to solve for the number of moles (n):
n = PV / RT
Substituting the values:
n = (1.2 atm * 2.5 L) / (0.0821 L·atm/(mol·K) * 298.15 K)
n = 0.0271 moles
Therefore, approximately 0.0271 moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm and 25 degrees Celsius.
Use PV = nRT. Don't forget to change T to Kelvin.
Note the correct spelling of celsius.