Posted by **LeAnn/Emergency Help Please** on Saturday, February 27, 2010 at 8:37pm.

This Question is in multiple sections.

f(x)= -2x^2+2x+10 is the problem

1)What is the x coordinate of vertex in simplified fraction?

2)What is the y coordinate of vertex in simplified fraction?

3)What is the line of symmetry?

4)What is the maximum/minumum of f(x)?

5)The value of f(1/2)=21/2 is minimum or maximum?

Can you please explain these steps to me in detail so that I get it. I'm preparing for a final in a couple days and have a couple last minute questions about certain problems on my algebra before I do my final. Thank You!!!

- Algebra 1B -
**bobpursley**, Saturday, February 27, 2010 at 9:12pm
1). Put the equation in the form of

y= a(x-h)^2+k

Then the vertex will be at h,k

y=-2(x^2-x-5)=-2(x^2-x+1/4)+10+1/2

y=-2(x-1/2)^2+ 10.5

so h=1/2, k= 10.5

line of symettry is as x=h

max.min is at x=h, so max is 10.5

- Algebra 1B -
**LeAnn/Emergency Help Please**, Saturday, February 27, 2010 at 9:35pm
Thank you!!!! Now, can you please tell me how to choose the correct graphing without actually seeing everything right in front of you?

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