Homework Help: Algebra 1B

Posted by LeAnn/Emergency Help Please on Saturday, February 27, 2010 at 8:37pm.

This Question is in multiple sections.
f(x)= -2x^2+2x+10 is the problem
1)What is the x coordinate of vertex in simplified fraction?
2)What is the y coordinate of vertex in simplified fraction?
3)What is the line of symmetry?
4)What is the maximum/minumum of f(x)?
5)The value of f(1/2)=21/2 is minimum or maximum?

Can you please explain these steps to me in detail so that I get it. I'm preparing for a final in a couple days and have a couple last minute questions about certain problems on my algebra before I do my final. Thank You!!!

Algebra 1B - bobpursley, Saturday, February 27, 2010 at 9:12pm
1). Put the equation in the form of
y= a(x-h)^2+k

Then the vertex will be at h,k

y=-2(x^2-x-5)=-2(x^2-x+1/4)+10+1/2
y=-2(x-1/2)^2+ 10.5
so h=1/2, k= 10.5
line of symettry is as x=h
max.min is at x=h, so max is 10.5
Algebra 1B - LeAnn/Emergency Help Please, Saturday, February 27, 2010 at 9:35pm
Thank you!!!! Now, can you please tell me how to choose the correct graphing without actually seeing everything right in front of you?

Answer this Question

Related Questions

Math - When completing the square: 5x^2 + 10x - 20 5 ( x^2 + 2x) -20 = 0 5 ( x...
algebra 2 - what is the y-intercept, the x-coordinate of the vertex and the ...
Algebra2 - Complete parts a – c for each quadratic function: a. Find the y-...
Math33333 - Please help me! Problem: x+2 x-3 _________ - _________ 2x^2+5x+2 2x^...
Algebra Functions - I cannot for the life of me remember how to do this- Find ...
algebra - solve the polynomial y=2x^2-4x+1 For Further Reading algebra - Reiny, ...
ALGEBRA - I have worked this problem out and just need confirmation. 15 + 2x - 5...
Algebra - Need help with this problem, 2x+y=6 solve for y 2x+y=6 subtract 2x ...
ALGEBRA - Find the vertex, the line of symmetry, the maximum or minimum value of...
Rational Expression - (x+1/2x-1 - x-1/2x+1) * (2x-1/x - 2x-1/x^2) (x+1/2x-1 - x-...

For Further Reading

First Name:
School Subject:
Answer: