Posted by LeAnn/Emergency Help Please on Saturday, February 27, 2010 at 8:37pm.
This Question is in multiple sections.
f(x)= 2x^2+2x+10 is the problem
1)What is the x coordinate of vertex in simplified fraction?
2)What is the y coordinate of vertex in simplified fraction?
3)What is the line of symmetry?
4)What is the maximum/minumum of f(x)?
5)The value of f(1/2)=21/2 is minimum or maximum?
Can you please explain these steps to me in detail so that I get it. I'm preparing for a final in a couple days and have a couple last minute questions about certain problems on my algebra before I do my final. Thank You!!!

Algebra 1B  bobpursley, Saturday, February 27, 2010 at 9:12pm
1). Put the equation in the form of
y= a(xh)^2+k
Then the vertex will be at h,k
y=2(x^2x5)=2(x^2x+1/4)+10+1/2
y=2(x1/2)^2+ 10.5
so h=1/2, k= 10.5
line of symettry is as x=h
max.min is at x=h, so max is 10.5

Algebra 1B  LeAnn/Emergency Help Please, Saturday, February 27, 2010 at 9:35pm
Thank you!!!! Now, can you please tell me how to choose the correct graphing without actually seeing everything right in front of you?
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