Help please
h+9/h-1 divided by 2h+18/h-5
multiplying by the reciprocal of the divisor..
(h+9)(h-5)/(h-1)(2(h+9))
(h-5)/2(h-1)
To simplify the expression (h+9)/(h-1) divided by (2h+18)/(h-5), you can follow these steps:
Step 1: Flip the second fraction and change the division to multiplication.
Dividing by a fraction is the same as multiplying by its reciprocal. So, the expression becomes:
(h+9)/(h-1) multiplied by (h-5)/(2h+18).
Step 2: Factorize where possible.
The denominator of the first fraction, (h-1), and the denominator of the second fraction, (2h+18), can both be factored.
(h-1) = 1(h-1)
(2h+18) = 2(h+9).
Step 3: Simplify and cancel out common factors.
Now, rewrite the expression with the factored denominators and cancel any common factors:
[(h+9)/(h-1)] * [(h-5)/(2h+18)]
= [(h+9)/(1(h-1))] * [(1(h-5))/(2(h+9))]
= [(h+9)/(h-1)] * [(h-5)/(2(h+9))]
= [(h+9)/(h+9)] * [(h-5)/(2(h-1))]
= (h-5)/(2(h-1)).
Therefore, the simplified expression is (h-5)/(2(h-1)).