Wednesday

August 27, 2014

August 27, 2014

Posted by **LALA** on Saturday, February 27, 2010 at 3:03pm.

f(t)= 20- 30/rooot 9 + t^2

heres how i did it

f'(x)= 20' - 30/root(9+t^2) '

= 0 - 30/root(9+t^2) '

(Quotient rule)

f'(x)= 30' (root(9+t^2) - 30(root(9+t^2) '

f'(x)= -30(0.5(9+t^2)^-0.5) (2t)

the answer at the back of the book is 30t/(9+t^2)^1/2.... but i dont knohow to get it.

**Related Questions**

Calculus I - Find the derivative ** (sq root) y = (square root) x + (2nd sq root...

Calculus - Any help would be much appreciated with the steps involved in each ...

Calculus - Any help would be much appreciated with the steps involved in each ...

calculus - 6. What is the derivative of y = square root of 3x ? a.dy/dx = square...

Calculus/Logarithms - Find the derivative of f(x) = (square root of x)(ln x). ...

Chain Rule - Any help would be much appreciated with the steps involved in each ...

Calculus - find derivitive of 1/square root of x 1/square root of x = x^(-1/2) ...

math, calculus - find the derivative of the function y= integral from square ...

Calculus - Find the functions a) f o g, b) g o f, c) f o f, d) g o g, and their ...

CALCULUS - Determine the derivative of the function: Y=1 / (Sq.root of (3x-1) I...