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January 30, 2015

January 30, 2015

Posted by **LALA** on Saturday, February 27, 2010 at 3:03pm.

f(t)= 20- 30/rooot 9 + t^2

heres how i did it

f'(x)= 20' - 30/root(9+t^2) '

= 0 - 30/root(9+t^2) '

(Quotient rule)

f'(x)= 30' (root(9+t^2) - 30(root(9+t^2) '

f'(x)= -30(0.5(9+t^2)^-0.5) (2t)

the answer at the back of the book is 30t/(9+t^2)^1/2.... but i dont knohow to get it.

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