a skydiver experiences a downwar force due to gravity of 700 N and an upward force of air resistance of 570 N. The mass of the skydiver is 65 kg. What is the downward acceleration in meters/second squared of the skydiver?

To find the downward acceleration of the skydiver, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = m * a).

In this case, the net force acting on the skydiver is the difference between the downward force due to gravity and the upward force of air resistance.

Net force = Force due to gravity - Force of air resistance
= 700 N - 570 N
= 130 N

Now, we can plug the net force and mass of the skydiver into Newton's second law equation to find the acceleration.

130 N = 65 kg * a

By rearranging the equation, we can solve for the acceleration (a).

a = 130 N / 65 kg
a = 2 m/s²

Therefore, the downward acceleration of the skydiver is 2 m/s².