Homework Help: Physics

Posted by Anonymous on Friday, February 26, 2010 at 12:10pm.

A heavy piece of hanging sculpture is suspended by a 90 cm long, 5.0 g steel wire. When the
wind blows hard, the wire hums at its fundamental frequency of 80 Hz. What is the mass of the
sculpture?

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Velocity=(0.9)(80)=72m/s

T=V^2*u
=(72)^2*(0.005kg/0.9m)
=28.8 N

T=W
28.8=(mass sculpture + mass wire)*g

..im not sure where I am going wrong...or if any of this is correct..

Physics - bobpursley, Friday, February 26, 2010 at 12:28pm
velocityalongstring= sqrt(tension/mass/length)

velocityalongstring=sqrt(Mass*g*.9/.005)
but the string is one half wavelength long (fixed at both ends), so
from the wave equation
frequency*wavelenth= velocity
frequency*2*.90=sqrt(Mass*9.8*.9/.005)
put in 80 hz, solve for mass of the weight.
Physics - bobpursley, Friday, February 26, 2010 at 12:31pm
oops, change my .005kg to .05kg

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