Two forces, of magnitudes F_1 = 80.0 N and F_2 = 25.0 N, act in opposite directions on a block, which sits atop a frictionless surface. Initially, the center of the block is at position x_i = -4.00 cm. At some later time, the block has moved to the right, and its center is at a new position, x_f = 2.00 cm. Find the work W_1 done on the block by the force of magnitude F_1 = 80.0 N as the block moves from x_i = -4.00 cm to x_f = 2.00 cm.
college physics - bobpursley, Thursday, February 25, 2010 at 9:15am
work doneby F1=80*.06 joules
work doneby F2=-25*.06