Posted by **GGIFT** on Thursday, February 25, 2010 at 8:36am.

with multiplying this:

9y^2-9)(8y^2-9y+3)

I have:

8y^2(y^2-9)-9y(y^2-9)+3(y^-9) THEN

8y^2*y^2-9-9y*y^2-9+3*y^2-9.... THEN

8y^8 - 6 ???

I think that I am lost

- ALGEBRA -
**Reiny**, Thursday, February 25, 2010 at 8:56am
(9y^2-9)(8y^2-9y+3)

= 72y^4 - 81y^3 + 27y^2 - 72y^2 + 81y - 27

(can you see what I did ?)

= 72y^4 - 81y^3 - 45y^2 + 81y - 27

(the y^2's were the only "like" terms )

- ALGEBRA -
**GGIFT**, Thursday, February 25, 2010 at 9:00am
OOOPPPPSS!!!

I wrote the problem wrong...

Multiply (y^2)(8y^2-9y+3)

then go with the first part of my 'THEN'

- ALGEBRA -
**Reiny**, Thursday, February 25, 2010 at 9:04am
Now it is easier

(y^2)(8y^2-9y+3)

just multiply the y^2 by each of the terms inside

= 8y^4 - 9y^3 + 3y^2

All done, since none of the terms are "like"

- ALGEBRA -
**GGIFT**, Thursday, February 25, 2010 at 9:22am
and that's it??? That's right, it cannot be simplified b/c of no like terms!!!

WHEW!!!

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