Posted by GGIFT on Thursday, February 25, 2010 at 8:36am.
with multiplying this:
9y^29)(8y^29y+3)
I have:
8y^2(y^29)9y(y^29)+3(y^9) THEN
8y^2*y^299y*y^29+3*y^29.... THEN
8y^8  6 ???
I think that I am lost

ALGEBRA  Reiny, Thursday, February 25, 2010 at 8:56am
(9y^29)(8y^29y+3)
= 72y^4  81y^3 + 27y^2  72y^2 + 81y  27
(can you see what I did ?)
= 72y^4  81y^3  45y^2 + 81y  27
(the y^2's were the only "like" terms )

ALGEBRA  GGIFT, Thursday, February 25, 2010 at 9:00am
OOOPPPPSS!!!
I wrote the problem wrong...
Multiply (y^2)(8y^29y+3)
then go with the first part of my 'THEN'

ALGEBRA  Reiny, Thursday, February 25, 2010 at 9:04am
Now it is easier
(y^2)(8y^29y+3)
just multiply the y^2 by each of the terms inside
= 8y^4  9y^3 + 3y^2
All done, since none of the terms are "like"

ALGEBRA  GGIFT, Thursday, February 25, 2010 at 9:22am
and that's it??? That's right, it cannot be simplified b/c of no like terms!!!
WHEW!!!
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