for subtracting this problem:
(0.04x^3-0.03x^2+0.02x)-(0.03x^3+0.08x^2-6)
I know to change the signs of the second grouping. When I done that, I cam up with:
0.04x^3-0.03x^2+0.02x-0.03x^3-0.08x^2+6 THEN
.01x^3 - .11x^2 + 0.02x + 6.....is that right??
the signs are changed b/c i had to find the opposite of each term.
correct
thanks!!!
;-)
Yes, you are correct that to subtract the second grouping, you need to change the signs of each term in the second grouping. Let's go through the steps to arrive at the solution.
Step 1: Write down the problem.
(0.04x^3 - 0.03x^2 + 0.02x) - (0.03x^3 + 0.08x^2 - 6)
Step 2: Change the signs of the second grouping.
0.04x^3 - 0.03x^2 + 0.02x - 0.03x^3 - 0.08x^2 + 6
Step 3: Combine like terms.
(0.04x^3 - 0.03x^3) + (-0.03x^2 - 0.08x^2) + (0.02x) + 6
Simplifying further:
0.01x^3 - 0.11x^2 + 0.02x + 6
So, your final answer is:
0.01x^3 - 0.11x^2 + 0.02x + 6