acceleration due to gravity questions
Determine the time of fall when an object is dropped if the average velocity of the falling object was 12m/s?
More information is required. Didn't they tell you the distance fallen?
Divide it by the average velocity
no... but apparently when an object is falling its acceleration is 9.81m/s^2
To determine the time of fall when an object is dropped, given the average velocity of the falling object, you need to consider the acceleration due to gravity. The acceleration due to gravity is a constant value, approximately 9.8 m/s^2 on the surface of the Earth.
The formula you can use to solve this problem is:
v = u + at
Where:
- v is the final velocity (which is 0 m/s when the object hits the ground).
- u is the initial velocity (which is 12 m/s in this case since the object was dropped with an average velocity of 12 m/s).
- a is the acceleration (which is the acceleration due to gravity, -9.8 m/s^2).
- t is the time of fall (which is what we need to find).
Rearranging the equation to isolate t, we have:
t = (v - u) / a
Substituting the values into the equation, we have:
t = (0 - 12) / -9.8
Simplifying this equation, we get:
t ≈ 1.224 seconds
Therefore, the time of fall when the object is dropped, with an average velocity of 12 m/s, is approximately 1.224 seconds.