Posted by yuku on Wednesday, February 24, 2010 at 11:05pm.
There are many solutions possible. However, assuming you are doing factoring in math, we will limit ourselves with integral sides, i.e. the length of each side is an integer.
If we factor 48 into its factors, we get:
2,2,2,2,3
The possible sides formed by these factors, ignoring sides of unity (1), are:
2,3,6,8,16,24,...
By trial and error, we start with
2,3,8: V=48, A=2(2*3+3*8+8*2)=92 too big.
We try sides that are more equal to each other:
2,4,6: V=48, A=2(2*4+4*6+6*2)=88 OK
So one possible solution for the sides is 2,4 and 6.
thx MathMate
You are welcome!