A 24-µF capacitor has an electric potential difference of 30 V across it. What is the charge on the capacitor?
To find the charge on the capacitor, you can use the formula Q = C * V, where Q is the charge in coulombs, C is the capacitance in farads, and V is the potential difference in volts.
In this case, the capacitance (C) is given as 24 µF (microfarads) and the potential difference (V) is given as 30 V.
Before we plug in the values into the formula, remember that the unit of capacitance is farads, but we have the capacitance given in microfarads. To convert from microfarads (µF) to farads (F), we divide by 1,000,000.
So, the capacitance in farads (C) would be 24 µF divided by 1,000,000, which is 0.000024 F.
Now we can substitute the values into the formula:
Q = C * V
Q = 0.000024 F * 30 V
Calculating the multiplication gives:
Q = 0.00072 C
Therefore, the charge on the capacitor is 0.00072 coulombs (C), or you can say 720 microcoulombs (µC) since there are 1,000,000 microcoulombs in one coulomb.
To find the charge on the capacitor, we can use the formula:
Q = C * V
Where:
Q is the charge on the capacitor,
C is the capacitance, and
V is the electric potential difference.
Given:
C = 24 µF (microfarads)
V = 30 V
Now we can substitute these values into the formula:
Q = (24 µF) * (30 V)
First, let's convert the capacitance from microfarads to farads:
1 µF = 10^-6 F
Q = (24 * 10^-6 F) * (30 V)
Next, let's simplify the expression:
Q = 7.2 * 10^-4 F * V
Finally, we can calculate the value of Q:
Q = 7.2 * 10^-4 F * 30 V
Q = 0.0216 C
Therefore, the charge on the capacitor is 0.0216 C.