Posted by Paul on Wednesday, February 24, 2010 at 11:13am.
Posted by Paul on Friday, February 19, 2010 at 3:57am.
I have the function f(x)=e^x*sinNx on the interval [0,1] where N is a positive integer. What does it mean describe the graph of the function when N={whatever integer}? And what happens to the graph and to the value of the integral as N approaches infinity? Does the graph confirm the limiting behavior of the integral's value?
* Calculus  Damon, Friday, February 19, 2010 at 10:07am
well, e^0 is 1
and e^.5 = 1.64
and e^1 is 2.72
so it is a sine wave with increasing amplitude as you approach 1 and frequency increasing with N
The integral of e^ax sin bx dx is
[e^ax/(a^2+b^2)] [a sin bx b cos bx}here a = 1 and b = N
so
[e^x/(1+N^2)] [sin Nx  N cos Nx]
as N gets big
this looks like
e^x (N cos Nx)/N^2
or
(e^x/N)(cos Nx)
e^x is that small constant and cos Nx ranges between 1 and + 1 so as N gets big this goes to zero like 1/N
* Calculus  Paul, Wednesday, February 24, 2010 at 11:12am
But how did you arrive at "as N gets big this looks like e^x(NcosNx)/N^2?????

calculus  bobpursley, Wednesday, February 24, 2010 at 11:36am
Professor Damon is describing the integral, not the function.
Have you graphed this function? For various N?

calculus  Paul, Wednesday, February 24, 2010 at 12:11pm
Yes I have, but I don't understand why the integral would go to zero. And the description of the interval.

calculus  Paul, Wednesday, February 24, 2010 at 12:18pm
is it because every interval of one the integrals approach 1?

calculus  Paul, Wednesday, February 24, 2010 at 12:18pm
I meant to say zero

calculus  Paul, Wednesday, February 24, 2010 at 12:20pm
But then would this confirm the limiting behavior of the graph because at every interval up to infinity it would approaching zero?
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