Tuesday
September 2, 2014

Homework Help: Physics

Posted by Jess on Tuesday, February 23, 2010 at 11:20pm.

We learned in lecture that the magnetic force on a charge q
moving with velocity v in a magnetic field ~B has the form

F = q~v B

One important fact about the cross-product is that for two vectors A and B , the following is
true A B = −B A which may also be determined by using the right-hand-rule. A convenient
way to calculate a cross-product is to decompose the vectors involved into x,y and z components,
and then use the following basic cross-product results for the basis vectors,

x y = z , y z = x , z x = y

Using the result just stated, the cross-products in the opposite order produce a minus sign,

y x = −z , z y = −x , x z = −y

so one only needs to remember the first three identities above, and these other identities can be
easily remembered. For this problem, use these identities to calculate the magnetic force on a
particle with a charge q = 7μC in a magnetic field B = (5 10−5 T)y. Do the calculation for the
following three different velocities:

(a) v = v0x

(b) v = v0y

(c) v = v0 (x+y/suare root 2) where v0 = 5m/s

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