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January 25, 2015

January 25, 2015

Posted by **larry** on Tuesday, February 23, 2010 at 9:07pm.

i've been stuck for over an hour and don't know what to do

i dont know is this right

? = "+" or "-"

# = number

y=x

(x+1)squared + (y+1)squared = 6

i substitute y

(x+1)squared + (x+1)squared = 6

x squared + 2x + 1 + x squared + 2x + 1 = 6

2x squared + 4x + 2 = 6

2x squared + 4x - 4 = 0

2(x squared + 2x - 2) = 0

2(x ? #)(x ? #)

i get to here and now i am stuck

can u correct me if i did something wrong

please and thank you

- math -
**Reiny**, Tuesday, February 23, 2010 at 9:14pmYou did nothing wrong, but not every quadratic factors.

An easier way is not to expand it.

from

(x+1)^2 + (x+1)^2 = 6

2(x+)^2 = 6

(x+1)^2 = 3

x+1 = ± √3

x = -1 ± √3

take it from here

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