Posted by eddy on Tuesday, February 23, 2010 at 4:41pm.
see this very related problem:
http://www.jiskha.com/display.cgi?id=1266960070
Many if not most problems in physics are not solved by plugging directly into a single equation. It is better to prceed in logical steps using formulas you are familiar with.
In this case, the place to start is with conservation of energy. The vertical drop of the runway is
H = 15 sin 20 = 5.13
The Potential energy loss MgH equals the Kinetic Energy gain, so
MgH = (1/2) M V^2
V = sqrt(2 g H) = 100.3 m/s
(I used 9.81 m/s^2 for g)
Note that you did not need to use the mass for this one.
To do the second case, subtract friction work done
3000N*15 m = 45,000 J from the potential energy decrease, and solve for V again.
M g H - 45,000 = (1/2) M V^2
You will need to use the mass this time.
Two long, parallel wires separated by 30 cm each carry currents of 4.0 A in a horizontal direction.
B)Find if they are in opposite directions.
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