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Posted by on Tuesday, February 23, 2010 at 8:36am.

A dilute sulfuric acid solution that is 3.39 molality H2SO4 has a density of 1.18 g/mL. How many moles of H2SO4 are there in 375 mL of this solution?

  • chemistry - , Tuesday, February 23, 2010 at 3:16pm

    3.39 m = 3.39 moles (332.22 g) + 1 kg solvent.
    Mass of solution = 332.22g + 1,000g = 1332.22 grams.

    375 mL has a mass of what?
    mass = volume x density = 375 mL x 1.18 g/mL = 442.5 grams.

    g solute in 375 mL = 332.22g x (442.5/1332.22) = 110.35 g which is 110.35/98 = 1.126 moles H2SO4.

    Does that sound reasonable? How much solvent do we have in that 442.5 g. That will be 442.5-110.35 = 332.15 g
    and 1.126 mole/0.33215 kg = 3.39 m so I think it is reasonable.

  • chemistry - , Tuesday, February 23, 2010 at 3:41pm

    A couple of things I forgot to mention.
    1. I used 98 for the molar mass of H2SO4. That may not be close enough for you so you need to through the calculations and adjust numbers as appropriate.
    2. I used too many significant figures and you need to adjust them. The final answer should have no more than 3.

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