Posted by Trey on Tuesday, February 23, 2010 at 7:21am.
The length of DE equals the length of PR, which means that congruence is not impossible.
However, the coordinates of F is missing, so it is not possible to determine if DEF is congruent to PQR.
Well, by a simple vector calculation in the plane, you can easily find the last verticle. However, I interpret the question just as MathMate did.
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