Posted by **sakura_09** on Tuesday, February 23, 2010 at 1:33am.

Calculate the theoretical amount of CaCl2 that would be required to change the temperature of 50 mL of water from from temperature 20 degrees Celsius to 45 degrees Celsius. Remember that the heat lost during the dissociation is equal to the heat gained by the 50.0 mL of water. In order to do this, you will need the heat capacity of water. This value is 4.184 J/g-1 and assume that density of water is 1 g/mL.

- Chemisrty -
**DrBob222**, Tuesday, February 23, 2010 at 4:14pm
heat required is q.

q = mass water x specific heat water x delta T. Now all you need is the heat released when a mole of CaCl2 dissolves.

- Chemisrty -
**Tersa**, Sunday, October 17, 2010 at 12:33pm
can someone please explain this question more in detail

thank you

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