Posted by Kenny on Monday, February 22, 2010 at 9:12pm.
Could someone please help me with this question;
Find the tangent to the curve y=x^2-8x+14 which slope is -2. Show that this tangent touches the curve y= -x^2-4x+4. Find the point of contact.
Calculus - bobpursley, Monday, February 22, 2010 at 9:18pm
take the derivative of the first equation
x= 3 is where the tangent has the slope of -2
so the equation of that tangent line is
y=-2x+b to find b, you have to find y at x=3
now put that y into
y=-2x + b and solve for b.
Now you have the line. I will leave it up to you to show this line is tangent to the second curve, the process is very similar.
Calculus - Kenny, Monday, February 22, 2010 at 10:31pm
Thank you Bobpursley.
After doing what you told me, the point of contact I got is, (-1,7).
Is this correct?
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