Sunday

December 21, 2014

December 21, 2014

Posted by **Kenny** on Monday, February 22, 2010 at 9:12pm.

Find the tangent to the curve y=x^2-8x+14 which slope is -2. Show that this tangent touches the curve y= -x^2-4x+4. Find the point of contact.

Thank you.

- Calculus -
**bobpursley**, Monday, February 22, 2010 at 9:18pmtake the derivative of the first equation

y'=2x-8

-2=2x-8

x= 3 is where the tangent has the slope of -2

so the equation of that tangent line is

y=-2x+b to find b, you have to find y at x=3

y= x^2-8x+14=9-24+14

now put that y into

y=-2x + b and solve for b.

Now you have the line. I will leave it up to you to show this line is tangent to the second curve, the process is very similar.

- Calculus -
**Kenny**, Monday, February 22, 2010 at 10:31pmThank you Bobpursley.

After doing what you told me, the point of contact I got is, (-1,7).

Is this correct?

**Answer this Question**

**Related Questions**

Calculus - Consider the curve given by y^2 = 2+xy (a) show that dy/dx= y/(2y-x...

12th Grade Calculus - 1. a.) Find an equation for the line perpendicular to the ...

calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...

calculus - 1. Given the curve a. Find an expression for the slope of the curve ...

Calculus - Consider the curve y^2+xy+x^2=15. What is dy/dx? Find the two points ...

please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...

Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...

Calculus Help Please!!! - --- Find the slope m of the tangent to the curve y = ...

Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...

Calculus - There are two neighboring points P and Q on the curve f(x)=x^2 (a) ...