Posted by Kenny on Monday, February 22, 2010 at 9:12pm.
Could someone please help me with this question;
Find the tangent to the curve y=x^28x+14 which slope is 2. Show that this tangent touches the curve y= x^24x+4. Find the point of contact.
Thank you.

Calculus  bobpursley, Monday, February 22, 2010 at 9:18pm
take the derivative of the first equation
y'=2x8
2=2x8
x= 3 is where the tangent has the slope of 2
so the equation of that tangent line is
y=2x+b to find b, you have to find y at x=3
y= x^28x+14=924+14
now put that y into
y=2x + b and solve for b.
Now you have the line. I will leave it up to you to show this line is tangent to the second curve, the process is very similar.

Calculus  Kenny, Monday, February 22, 2010 at 10:31pm
Thank you Bobpursley.
After doing what you told me, the point of contact I got is, (1,7).
Is this correct?
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