Posted by **cody** on Monday, February 22, 2010 at 6:21pm.

what is the area of a regular quadrilateral (square) that has a radius of 10 square root of 2. The 10 square root of 2 is the x^2 (the hypotenuse) part of a 45-45-90.

- geometry -
**drwls**, Monday, February 22, 2010 at 6:28pm
What do you mean by the radius of a square? Are you referring to the inscribed circle or the circumscribed (outside) circle?

If 10 sqrt2 is the radius of a circumscribed circle, then the square inside the circle has side lengths of 20. The area is then 400.

- geometry -
**cody**, Monday, February 22, 2010 at 6:35pm
it is only a square, no circle. the radius i am refering to is from the corner point to the midpoint of the square. and from the midpoint there is a line going straight down, thus forth a 45-45-90. it is like dividing a sqaure into 4 equal sections, each corner is in 1/4 of the square. then take one section, and cut that straight in half from the midpoint to the corner. that line is the 10 sqrt of 2.

- geometry -
**drwls**, Monday, February 22, 2010 at 6:43pm
In that case it is like the radius of a circumscribed circle, and the answer I gave is the correct one.

- geometry -
**cody**, Monday, February 22, 2010 at 6:47pm
thank you

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