Thursday
March 23, 2017

Post a New Question

Posted by on Monday, February 22, 2010 at 1:54pm.

Find three consecutive integers such that the sum of the first and second is three mose than three times the third.

When I did the problem,I got a negative answer. Does that seem correct? Did I make any mistakes?

  • Math - , Monday, February 22, 2010 at 3:04pm

    Let a = the first number, b = the second number and c = the third number.

    Then, b = (a + 1) and c = (a + 2)

    Therefore, a + (a + 1) = 3(a + 2) + 3 yielding 2a + 1 = 3a + 6 + 3 making a = -8 and the three numbers -8, -7 and -6.

    -8 + -7 = 3(-6) + 3
    -15 = -18 + 3 = -15.

  • Math - , Monday, February 22, 2010 at 4:04pm

    How do you get -8 as a?

  • Math - , Monday, February 22, 2010 at 6:28pm

    Let a = the first number, b = the second number and c = the third number.

    Then, b = (a + 1) and c = (a + 2)

    Therefore, a + (a + 1) = 3(a + 2) + 3 yielding 2a + 1 = 3a + 6 + 3.
    .........2a + 1 = 3a + 9
    .........2a + 1 - 9 = 3a
    .........2a - 8 = 3a
    ............-8 = 3a - 2a
    ............-8 = a

    -8 + -7 = 3(-6) + 3
    -15 = -18 + 3 = -15.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question