Wednesday

September 3, 2014

September 3, 2014

Posted by **steve** on Monday, February 22, 2010 at 9:41am.

- algebra -
**drwls**, Monday, February 22, 2010 at 10:05amLet x be the number of ml that must be added. The amount of acid contained in the mix can be written two ways, and is:

0.15*80 + 0.20x = 0.18*(80 + x)

Solve for x

12 + 0.20x = 14.4 + 0.18x

0.02x = 2.4

x = 120 ml

**Answer this Question**

**Related Questions**

Algebra - how much pure acid must be added to 15 ounces of an acid solution ...

Algebra 2 - How much pure acid must be added to 6 milliliters of a 5% acid ...

Algebra 1 - Bunson Burner has 3 liters of a 10% acid solution. How much of pure ...

Algebra - 100mL of a solution contains 30 mL of acid; this is called a 30% acid ...

Math - Alg - How much pure acid must be added to a 30% acid solution to make a ...

Math - Alg - How much pure acid must be added to a 30% acid solution to make a ...

Solving Rational Equations - 100mL of a solution contains 30 mL of acid; this is...

Algebra - Solution A is 30% acid and solution B is 60% acid. How many gallons of...

Algebra - Suppose a 2% acid solution is mixed with a 3% acid solution. Find the ...

Algebra - Suppose a 2% acid solution is mixed with a 3% acid solution. Find the ...