Posted by Kelsey on Monday, February 22, 2010 at 5:40am.
1. 0.30 M NaNO3. You have 1 Na ion and 1 nitrate ion per molecule of NaNO3; therefore (Na^+) = (NO3^-) = 0.30 M.
2. You have 1 Mg ion and 1 sulfate ion per molecule of MgSO4; therefore, (Mg^+) = (SO4^-2) = 1.5 x 10^-2 M3.
3. C6H12O6 is an organic molecule; it doesn't ionize; therefore, the molecule concn is 2.00 x 10^-2 M.
4.You have diluted NaCl from 45.0 mL to 110 mL (45 mL + 65 mL = 110 mL) so the new concn NaCl is 0.272 M x (45.0/110.0) = ?? and that is the (Na^+) and (Cl^-).
Similarly, (NH4)2CO3 is
0.0247 M x (65.0/110.0) = ?? M.
?? M is the (CO3^-2) and 2 x ??M is the (NH4^+) (because there are two of them per molecule of (NH4)2CO3.
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