Posted by LALA on Sunday, February 21, 2010 at 1:37pm.
Sulfide added to the copper nitrate will ppt CuS.
CuS ==> Cu^+2 S^=
Remember CuS has a Ksp (solubility product) so the E value for that half cell will be changed to reflect the change of Cu concentration from the initial value (not listed in your post) to the new value present in a saturated solution of CuS.
b. Same thing for the iron solution.
Fe^+3 + S^= ==> Fe2S3 and there is a Ksp for Fe2S3
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