Posted by **Lyndse** on Sunday, February 21, 2010 at 11:59am.

A bag contains 7 red marbles, 2 blue marbles, and 1 green marble. If a marble is selected at random, what is the probability of choosing a marble that is not blue?

7+2+1=10 There are two blue marbles

So is the probability 1/5?

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**BubblyStar**, Sunday, February 21, 2010 at 12:02pm
Yes

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**Lyndse**, Sunday, February 21, 2010 at 12:10pm
Thank you!

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**Jai**, Wednesday, December 17, 2014 at 8:09am
Correct answer is 1-(2/10) => 8/10 => 4/5

in question it mentioned as not blue.

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**Anonymous**, Sunday, May 17, 2015 at 3:56pm
4/5

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**anonymous**, Thursday, November 5, 2015 at 10:39pm
4/5 is right

- YOU ARE ALL WRONG -
**addisyn**, Wednesday, April 20, 2016 at 6:18pm
YOU ARE ALL WRONG

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**amira**, Friday, April 22, 2016 at 6:54am
A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?

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**value**, Thursday, October 6, 2016 at 5:59pm
4+6=10 P(Y)=4/10=2/5 P(G)=6/10=3/5

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**Anonymous**, Thursday, December 8, 2016 at 7:16pm
7 black marbles and 19 blue marbles

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**katr**, Friday, December 9, 2016 at 2:39pm
The probability is 7/5

This event is very likely to happen

This event will not happen.

The probability is 1.

The probability is 0.

this can be the answers

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