Posted by Lyndse on .
A bag contains 7 red marbles, 2 blue marbles, and 1 green marble. If a marble is selected at random, what is the probability of choosing a marble that is not blue?
7+2+1=10 There are two blue marbles
So is the probability 1/5?

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BubblyStar,
Yes

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Lyndse,
Thank you!

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Jai,
Correct answer is 1(2/10) => 8/10 => 4/5
in question it mentioned as not blue. 
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Anonymous,
4/5

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anonymous,
4/5 is right

YOU ARE ALL WRONG 
addisyn,
YOU ARE ALL WRONG

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amira,
A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?

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value,
4+6=10 P(Y)=4/10=2/5 P(G)=6/10=3/5

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Anonymous,
7 black marbles and 19 blue marbles

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katr,
The probability is 7/5
This event is very likely to happen
This event will not happen.
The probability is 1.
The probability is 0.
this can be the answers 
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Anonymous,
juigytfrdfytguhi

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colo,
a