A bag contains 7 red marbles, 2 blue marbles, and 1 green marble. If a marble is selected at random, what is the probability of choosing a marble that is not blue?

7+2+1=10 There are two blue marbles

So is the probability 1/5?

Yes

Thank you!

Correct answer is 1-(2/10) => 8/10 => 4/5

in question it mentioned as not blue.

4/5

4/5 is right

YOU ARE ALL WRONG

A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?

4+6=10 P(Y)=4/10=2/5 P(G)=6/10=3/5

7 black marbles and 19 blue marbles

The probability is 7/5

This event is very likely to happen
This event will not happen.
The probability is 1.
The probability is 0.
this can be the answers