Posted by lucy on Sunday, February 21, 2010 at 3:02am.
The spring constant can be determined from the oscillatory motion. For this case, Newton's second law gives
[(m(d^2)x) / (d(t^2))] + kx = 0
where x is the displacement from the equilibrium position. The sample mass is suspended from the spring by a sample holder.
Does m in this formula include the mass of the sample holder?
A. No
B. Yes
C. None of the above

college physics  Anonymous, Monday, February 22, 2010 at 8:47pm
B. Yes
Answer This Question
Related Questions
 physics  The spring constant can be determined from the oscillatory motion. For...
 physics  When a 1.3kg mass was attached to a spring, the spring stretched 21cm ...
 Physics 203  A block with mass of 5.0kg is suspended from an ideal spring ...
 Physics  A body of mass m is suspended from a spring with spring constant k and...
 Physics  A 3.5 kg object is suspended from a spring of spring constant 725 N/m...
 Physics  A 3.5 kg object is suspended from a spring of spring constant 725 N/m...
 physics  A 1kg mass is suspended from a vertical spring with a spring constant ...
 Physics  A mass of 0.77 kg, hanging from a spring with a spring constant of 37 ...
 Physics  The length of a spring increases by 7.2 cm from its relaxed length ...
 physics  A body is suspended vertically from an ideal spring of spring constant...
More Related Questions