Posted by **lucy** on Sunday, February 21, 2010 at 3:02am.

The spring constant can be determined from the oscillatory motion. For this case, Newton's second law gives

[(m(d^2)x) / (d(t^2))] + kx = 0

where x is the displacement from the equilibrium position. The sample mass is suspended from the spring by a sample holder.

Does m in this formula include the mass of the sample holder?

A. No

B. Yes

C. None of the above

- college physics -
**Anonymous**, Monday, February 22, 2010 at 8:47pm
B. Yes

## Answer this Question

## Related Questions

- physics - The spring constant can be determined from the oscillatory motion. For...
- physics - When a 1.3kg mass was attached to a spring, the spring stretched 21cm...
- Physics - A mass of 0.77 kg, hanging from a spring with a spring constant of 37 ...
- Physics - A 3.5 kg object is suspended from a spring of spring constant 725 N/m...
- Physics - A 3.5 kg object is suspended from a spring of spring constant 725 N/m...
- Physics - You have a mass of 2 kg attached to a spring with a spring constant 18...
- physics - A block of mass m = 0.605 kg is fastened to an unstrained horizontal ...
- physics - Sir Robert Hooke (1635-1703), studied the elastic properties of ...
- Physics - An object is attached to a horizontal spring. It is initially ...
- physics - A particle vibrates in Simple Harmonic Motion with amplitude. What ...

More Related Questions