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Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time
the second cyclist started biking?
( This question is very hard, please help me, please help with the working. thanks )

  • maths -

    When the second cyclist starts, they are 18 miles apart. (3 hours times the speed of the first biker).

    After that, the distance between the bikers shrinks at a rate of 10 - 6 = 4 miles/hr.

    The distance between bikers becomes zero after 18/4 = 4.5 hours. That is when the late-starting biker [passes the other.

  • maths -


    let the time taken from when the second rider leaves till they meet be t hours

    10t = 6t + 18 , (their distances are the same)
    4t = 18
    t = 4.5

  • maths -

    thanks a lot !!

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