Posted by **thommini** on Saturday, February 20, 2010 at 6:53am.

Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time

the second cyclist started biking?

( This question is very hard, please help me, please help with the working. thanks )

- maths -
**drwls**, Saturday, February 20, 2010 at 8:15am
When the second cyclist starts, they are 18 miles apart. (3 hours times the speed of the first biker).

After that, the distance between the bikers shrinks at a rate of 10 - 6 = 4 miles/hr.

The distance between bikers becomes zero after 18/4 = 4.5 hours. That is when the late-starting biker [passes the other.

- maths -
**Reiny**, Saturday, February 20, 2010 at 9:02am
OR

let the time taken from when the second rider leaves till they meet be t hours

10t = 6t + 18 , (their distances are the same)

4t = 18

t = 4.5

- maths -
**thommini**, Sunday, February 21, 2010 at 8:10am
thanks a lot !!

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