I need to sketch a 45 deg - 45 deg - 90 deg triangle and indicate the lengths of each side assuming the hypotenuse is = to 1 meter
This not about physics.
Use graph paper or an straight-edge with a right angle corner to draw two lines at right angles meeting at a point. Make the two lines of equal length. Draw the hypotentuse between the other two ends of the lines. If you choose a scale that calls the hypotenuse length 1 meter, the two equal sides will have a length of 0.707 meters. 1/(sqrt2)
In the figure, charge = 2.1 × is placed at the origin and charge is placed on the -axis, at = -0.20 m. Where along the -axis can a third charge be placed such that the resultant force on this third charge is zero?
Express your answer using two significant figures.
To sketch a 45-45-90 triangle, follow these steps:
1. Start by drawing a horizontal line segment.
2. Choose a point on the left end of the line segment as the vertex of your triangle.
3. From this vertex, draw a line segment at a 45-degree angle upwards.
4. From the same vertex, draw another line segment at a 45-degree angle downwards, intersecting the first line segment at right angles.
5. Connect the endpoints of the two line segments with a straight line to complete the triangle.
Now, let's label the lengths of each side of the triangle. In a 45-45-90 triangle, the ratio of the side lengths is 1:1:√2.
Since you mentioned that the hypotenuse is equal to 1 meter, we can assign the length of the hypotenuse as 1 meter. Let's call this side length "a."
The other two sides of the triangle will also have the same length, so both can be labeled as "b."
By the ratio mentioned earlier, the length of each of these two sides (b) will be equal to 1/√2, which can be simplified as √2/2.
To summarize, the lengths of the sides of the triangle are as follows:
- Hypotenuse (a) = 1 meter
- Other two sides (b) = √2/2 meters