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The pH of a 1.2 M solution of an unknown weak base is 10.65. What is the Kb for the base?

  • chemistry - ,

    BOH ==> B^+ + OH^-

    Kb = (B^+)(OH^-)/(BOH)
    You know pH, convert to pOH, then to (OH^-) and substitute into Ka expression. For (BOH), substitute 1.2 - (OH^-) and solve for Kb.

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