An electron travels at a speed of 4.0×104 m/s through a uniform magnetic field whose magnitude is 1.4×10−3 T.
What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field are perpendicular? F= N
What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field make an angle of 45 ? F= N
What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field are parallel?
F= N
What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field are exactly opposite? F= N
45
"You don't seem to be willing to take step one in answering these problems yourself. "
What good is just knowing a formula?
drwis is a awful for that answer
To calculate the magnitude of the magnetic force, you can use the formula:
F = q * v * B * sin(theta)
Where:
F is the magnetic force
q is the charge of the particle (in this case, the charge of the electron = -1.6 x 10^-19 C)
v is the velocity of the particle (4.0 x 10^4 m/s)
B is the magnitude of the magnetic field (1.4 x 10^-3 T)
theta is the angle between the velocity vector and the magnetic field vector.
Now, let's calculate the magnitude of the magnetic force for each scenario:
1. When the velocity and the magnetic field are perpendicular (theta = 90 degrees):
F = (-1.6 x 10^-19 C) * (4.0 x 10^4 m/s) * (1.4 x 10^-3 T) * sin(90°)
= 5.6 x 10^-15 N
The magnitude of the magnetic force on the electron is 5.6 x 10^-15 N.
2. When the velocity and the magnetic field make an angle of 45 degrees:
F = (-1.6 x 10^-19 C) * (4.0 x 10^4 m/s) * (1.4 x 10^-3 T) * sin(45°)
= 2.8 x 10^-15 N
The magnitude of the magnetic force on the electron is 2.8 x 10^-15 N.
3. When the velocity and the magnetic field are parallel (theta = 0 degrees):
F = (-1.6 x 10^-19 C) * (4.0 x 10^4 m/s) * (1.4 x 10^-3 T) * sin(0°)
= 0 N
The magnitude of the magnetic force on the electron is 0 N. Since the angle is 0 degrees, the sine of 0 degrees is 0, resulting in no force.
4. When the velocity and the magnetic field are exactly opposite (theta = 180 degrees):
F = (-1.6 x 10^-19 C) * (4.0 x 10^4 m/s) * (1.4 x 10^-3 T) * sin(180°)
= 0 N
The magnitude of the magnetic force on the electron is 0 N. Since the angle is 180 degrees, the sine of 180 degrees is 0, resulting in no force.
You don't seem to be willing to take step one in answering these problems yourself.
You should have been taught the laws
F = q V x B and Ampere's law as part of your course work
q is the (negative) electron charge in this case.