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September 1, 2014

September 1, 2014

Posted by **rmz** on Friday, February 19, 2010 at 12:34pm.

All I know is that you would get the wrong slope for the ordered pairs, I do not know why. Can anyone help?

- math -
**drwls**, Friday, February 19, 2010 at 5:00pmCorrect slope = m = (y2-y1)/(x2-x1) = (y1-y2)/(x1-x2)

for a line between (x1,y1) and (x2,y2)

If the y2-y1 in the numerator is not consistent with the x2-x1 in the denominator, you get the wrong sign for the slope. For example,

(y2-y1)/(x1-x2) = -m

- math -
**rmz**, Friday, February 19, 2010 at 5:36pmthanks now I know exactly what the situation is.

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