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March 31, 2015

March 31, 2015

Posted by **Paul** on Friday, February 19, 2010 at 3:57am.

- Calculus -
**Damon**, Friday, February 19, 2010 at 10:07amwell, e^0 is 1

and e^.5 = 1.64

and e^1 is 2.72

so it is a sine wave with increasing amplitude as you approach 1 and frequency increasing with N

The integral of e^ax sin bx dx is

[e^ax/(a^2+b^2)] [a sin bx -b cos bx}here a = 1 and b = N

so

[e^x/(1+N^2)] [sin Nx - N cos Nx]

as N gets big

this looks like

e^x (-N cos Nx)/N^2

or

(-e^x/N)(cos Nx)

e^x is that small constant and cos Nx ranges between -1 and + 1 so as N gets big this goes to zero like 1/N

- Calculus -
**Paul**, Friday, February 19, 2010 at 11:51pmNow how would you describe the graph of this function when say N=5, N=10, and N=100?

And what does it mean does the graph confirm the limiting behavior of the integral's value?

- Calculus -
**Paul**, Wednesday, February 24, 2010 at 11:12amBut how did you arrive at "as N gets big this looks like e^x(-NcosNx)/N^2?????

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