The circumference of a sphere was measured to be 88000 cm with a possible error of 050000 cm. Use linear approximation to estimate the maximum error in the calculated surface area.
Estimate the relative error in the calculated surface area.
Oops the 88000 is supposed to be 88 cm and 0.5 cm
Circumference, C=88 cm
C = 2πr
dA/dr = 2πr
Using linear approximation:
δA = 2πr δr
=88 cm * 0.5 cm