find the roots of -25(x)cubed+100x
someone please, please answer
-25x (x^2-4)
x^2 = x squared
I hope this helps.
To find the roots of the equation -25(x^3) + 100x, we can set the equation equal to zero and solve for x.
-25(x^3) + 100x = 0
Factoring out x from both terms gives:
x(-25x^2 + 100) = 0
Now, we can solve each factor separately.
First, we have x = 0 as a solution.
Next, we solve -25x^2 + 100 = 0 for x^2:
-25x^2 + 100 = 0
Divide both sides by -25:
x^2 - 4 = 0
Now, we can factor x^2 - 4 using the difference of squares formula, which states that a^2 - b^2 = (a + b)(a - b):
(x + 2)(x - 2) = 0
Setting each factor equal to zero gives:
x + 2 = 0 or x - 2 = 0
Solving these equations gives:
x = -2 or x = 2
Therefore, the roots of the equation -25(x^3) + 100x = 0 are x = -2, x = 0, and x = 2.