Posted by **Help!** on Thursday, February 18, 2010 at 9:26pm.

In a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a calculus book along the dorm hallway. If the 3.5 kg book is pushed from rest through a distance of 0.88 m by the horizontal 25 N force from the broom and then has a speed of 1.63 m/s, what is the coefficient of kinetic friction between the book and floor?

- college physics -
**drwls**, Thursday, February 18, 2010 at 10:28pm
Work done by broom = Kinetic energy increase + work done against fraction

Compute the friction work using that equation. Divide it by the distance moved to get the friction force. Use that to get the friction coefficient

- college physics -
**lilly**, Tuesday, October 20, 2015 at 4:44am
m = 3.5kg

x = 0.88m

f = 25N

speed = 1.63m/s

coefficient of kinetic friction = ?

we know, fk=fnormal*coefficient of kinetic friction

where fk = kinetic frictional force

so, fk= mg*coefficient

fk=3.5*9.8*cefficient

a=?

so applying the equation

v^2=u^2+2ax

a= 1.1m/s^2

fnet=ma

so, ma=3.5*9.8*coefficient

cefficient= 0.11

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