Posted by Help! on Thursday, February 18, 2010 at 9:26pm.
In a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a calculus book along the dorm hallway. If the 3.5 kg book is pushed from rest through a distance of 0.88 m by the horizontal 25 N force from the broom and then has a speed of 1.63 m/s, what is the coefficient of kinetic friction between the book and floor?

college physics  drwls, Thursday, February 18, 2010 at 10:28pm
Work done by broom = Kinetic energy increase + work done against fraction
Compute the friction work using that equation. Divide it by the distance moved to get the friction force. Use that to get the friction coefficient

college physics  lilly, Tuesday, October 20, 2015 at 4:44am
m = 3.5kg
x = 0.88m
f = 25N
speed = 1.63m/s
coefficient of kinetic friction = ?
we know, fk=fnormal*coefficient of kinetic friction
where fk = kinetic frictional force
so, fk= mg*coefficient
fk=3.5*9.8*cefficient
a=?
so applying the equation
v^2=u^2+2ax
a= 1.1m/s^2
fnet=ma
so, ma=3.5*9.8*coefficient
cefficient= 0.11
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