How do you write these two equations in slope intercept form?
x-5y-10=0
5x+2y+10=0
y= x/5-2 and Y= -5/2-5
How do you get these answers?
To write these two equations in slope-intercept form (y = mx + b), we need to isolate the y variable on one side of the equation.
1) Let's start with the first equation: x - 5y - 10 = 0.
Step 1: Move the x term to the other side by adding 10 to both sides.
x - 5y = 10
Step 2: Move the coefficient of y to the other side by subtracting x from both sides.
-5y = -x + 10
Step 3: Divide both sides by -5 to isolate y.
y = (1/5)x - 2
Therefore, the first equation in slope-intercept form is y = (1/5)x - 2.
2) Now, let's move on to the second equation: 5x + 2y + 10 = 0.
Step 1: Move the constant term (10) to the other side of the equation by subtracting 10 from both sides.
5x + 2y = -10
Step 2: Move the coefficient of x to the other side of the equation by subtracting 5x from both sides.
2y = -5x - 10
Step 3: Divide both sides by 2 to isolate y.
y = (-5/2)x - 5
Therefore, the second equation in slope-intercept form is y = (-5/2)x - 5.