Posted by **Hannah** on Thursday, February 18, 2010 at 1:12pm.

1) Find all the solutions of the equation in the interval (0,2pi).

sin 2x = -sqrt3/2

I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them.

2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi

Now I know that I have to divide by 2 but that is where I an not sure.

x = 4pi/6 + npi x=10pi/3 + npi

Is that correct???

## Answer this Question

## Related Questions

- Pre-Cal(Please check) - 1) Find all the solutions of the equation in the ...
- Pre-Cal (Please help) - Find all the soultions of the equation in the interval...
- Pre-Cal - Find all the soultions of the equation in the interval (0,2pi) sin 2x...
- Math - 1. On the interval [0, 2pi] what are the solutions to the equation ...
- Pre-Cal(Please check) - Approximate the equation's solutions in the interval (0,...
- Pre-Cal - Find all the solutions of the equation in the interval (0,2pip) sin(x...
- Pre-Cal(Urgent!!) - Find all the solutions of the equation in the interval (0,...
- Precalculus check answers help! - 1. Which expression is equivalent to cos ...
- Pre-Cal(Please help) - Approximate the equation's soultions in the interval (o...
- Pre-Calc - Find all solutions of the equation in the interval [0, 2pi). Show all...