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September 17, 2014

September 17, 2014

Posted by **Rony** on Thursday, February 18, 2010 at 12:56pm.

-What is the total resistance of the load?

-What is the current in R3

-What is the potential difference across R2?

- physics -
**drwls**, Thursday, February 18, 2010 at 1:09pmFirst get the effective resistance of R1 and R2 in series. It is 24 ohms. That in parallel with 8 ohms has an overall circuit resistance Reff geiven by

1/Reff = 1/24 + 1/8 = 4/24 = 1/6

Therefore Reff = 6 ohms.

The total current going through the circuit (battery) is

I = V/Reff = 1.0 amperes.

The total current going through the R1 and R2 is V/(R1+R2) = 6/24 = 0.25 A

The potential drop across R2 is

0.25A*9 ohms = 2.25 V

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