Tuesday
September 23, 2014

Homework Help: AP Chemistry

Posted by Anonymous on Wednesday, February 17, 2010 at 8:11pm.

A 1.2M NaOCl solution is prepared by dissolving solid NaOCL in distilled water at 298K. The hydrolysis reaction

OCl-(aq) + H2O(l) --> HOCl(aq) + OH-(aq) occurs.

a. Calculate the value of the equilibrium constant at 298K for the hydrolysis reaction.
b. Calculate the value of [OH-] in the 1.2M NaOCl solution at 298K.

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So far I have the expression:
K= {[HOCl][OH-]}/[OCl-]

...but I don't understand how to find K if you're only given the concentration of NaOCl. Help???

Thanks!

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