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March 25, 2017

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Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25°C. Calculate the molarity of a solution of acetic acid made by dissolving 10.00 mL of glacial acetic acid at 25°C in enough water to make 150.0 mL of solution.

  • Chemistry - ,

    density glacial acetic acid is 1.049 g/mL. How many grams acetic acid do we have in the 10.00 mL glacial acetic acid? That will be 1.049 g/mL x 10.00 mL = 10.49 grams. How many moles is that?
    10.49/60 (you look up the molar mass and do it exactly following my estimates) = 0.17 moles.
    M = moles/L
    M = 0.17/0.150 L = ??

  • Chemistry - ,

    0.350

  • Chemistry - ,

    0.8418

  • Chemistry - ,

    about 1.16 M

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